2[f+3]+4f=6+6f

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Solution for 2[f+3]+4f=6+6f equation:


Simplifying
2[f + 3] + 4f = 6 + 6f

Reorder the terms:
2[3 + f] + 4f = 6 + 6f
[3 * 2 + f * 2] + 4f = 6 + 6f
[6 + 2f] + 4f = 6 + 6f

Combine like terms: 2f + 4f = 6f
6 + 6f = 6 + 6f

Add '-6' to each side of the equation.
6 + -6 + 6f = 6 + -6 + 6f

Combine like terms: 6 + -6 = 0
0 + 6f = 6 + -6 + 6f
6f = 6 + -6 + 6f

Combine like terms: 6 + -6 = 0
6f = 0 + 6f
6f = 6f

Add '-6f' to each side of the equation.
6f + -6f = 6f + -6f

Combine like terms: 6f + -6f = 0
0 = 6f + -6f

Combine like terms: 6f + -6f = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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